May 30th, 2019 by Aziz Lokhandwala
The function can be given as: $$f(x) = {e^{{x^{1\over 2}}}} + 1 + {|ln|(ln...xtimes)|}$$'x' belongs to N U {0}
Deviations are possible with values after square of numbers, for example numbers after 4 ,9, 16, 25,... and numbers after above squares are: 5,10, 17,... But excluding above values of 'x', you can have prime numbers sequence in continuation.
If anyone can find a proof for this, he/she will be awarded with a great prize amount.
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